UVa 10363 - Tic Tac Toe (check validity if Tic Tac Toe game, tricky)

Link: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=15&page=show_problem&problem=1304
Sol:

#include <iostream>
	using namespace std;
	bool winner(char mat[][3], char c) {
	if (mat[0][0] == c && mat[0][1] == c && mat[0][2] == c)
	return true;
	if (mat[1][0] == c && mat[1][1] == c && mat[1][2] == c)
	return true;
	if (mat[2][0] == c && mat[2][1] == c && mat[2][2] == c)
	return true;
	if (mat[0][0] == c && mat[1][0] == c && mat[2][0] == c)
	return true;
	if (mat[0][1] == c && mat[1][1] == c && mat[2][1] == c)
	return true;
	if (mat[0][2] == c && mat[1][2] == c && mat[2][2] == c)
	return true;
	if (mat[0][0] == c && mat[1][1] == c && mat[2][2] == c)
	return true;
	if (mat[2][0] == c && mat[1][1] == c && mat[0][2] == c)
	return true;
	return false;
	}
	void print(char mat[][3]) {
	for (int i = 0; i < 3; i++) {
	for (int j = 0; j < 3; j++) {
	cout << mat[i][j];
	}
	cout << endl;
	}
	}
	int main() {
	char mat[3][3];
	int tc, xnum, onum;
	bool xwin, owin;
	cin >> tc;
	while (tc--) {
	xnum = onum = 0;
	for (int i = 0; i < 3; i++)
	for (int j = 0; j < 3; j++) {
	cin >> mat[i][j];
	if (mat[i][j] == 'X')
	xnum++;
	if (mat[i][j] == 'O')
	onum++;
	}
	//cout << xnum << " " << onum << endl;
	xwin = winner(mat, 'X');
	owin = winner(mat, 'O');
	//cout << xwin << " " << owin << endl;
	bool result = false;
	if (xwin && owin)
	result = false;
	else if (xwin && (xnum == (onum + 1)))
	result = true;
	else if (xwin && (xnum != (onum + 1))) // need to add this, because of the xwin and xnum == onum
	result = false;
	else if (owin && (xnum == onum))
	result = true;
	else if (owin && (xnum != onum)) // need to add this, because of the owin and xnum == onum
	result = false;
	else if ((xnum == onum) || (xnum == (onum + 1)))
	result = true;
	if (result)
	cout << "yes" << endl;
	else
	cout << "no" << endl;
	}
	}